Question

6. Find two numbers such that the sum of thrice the first and the second is
142 and four times the first exceeds the second by 138.​

Answer 1

Answer:

Step-by-step explanation:

Let the first number be x and the second number be y

sum of thrice the and the second is 142

3x+y=142.       ------(1)

four times the first exceeds the second by 138

4x=y+138        -------(2)

solve (1) and (2)

x=40

y=22

Answer 2

Let one number be ' x ' amd the other no. be ' y '

ACCORDING TO THE QUESTION:-

${3x} + {y} = {142}$

${3x} + {y} - {142} = {0}$ ____( i )

${4x} = {138} + {y}$

${4x} - {y} - {138} = {0}$ _____( ii )

ADDING EQUATION ( i ) AND ( ii ) :-

${3x} + {y} - {142} = {0}$

+ ${4x} - {y} - {138} = {0}$

___________________________

${7x} \:\:\:\:\: {-280} = {0}$

${x} = \frac{280}{7}$

${x} = {40}$

SUBSTITUTING VALUE OF ' x ' IN EQ. ( i )

${3}×{40} + {y} - {142} = {0}$

${120} + {y} = {142}$

${y} = {142} - {120}$

${y} = {22}$

Answer:- ${x} = {40}$

${y} = {22}$