Question

6. Find two numbers such that the sum of thrice the first and the second
is 142, and four times the first exceeds the second by 138.
Please solve this question.​

Answer 1

Step-by-step explanation:

Let us assume, the two numbers are x and y.

Given:

3x + y = 142 ————1

And also given:

4x – y = 138

y = 4x – 138 ————–2

Substitute the value of y from eqn 2 in eqn 1

3x + 4x – 138 = 142

7x – 138 = 142

7x = 142 + 138

7x = 280

x = 40

Therefore, y = (4 * 40) – 138 = 22

The two numbers are 40 and 22

hope you understand it bro do hardwrok all the best.

Answer 2

Answer:

40,22

Step-by-step explanation:

Let x and y be the numbers such that 3x+y=142....(1) and 4x-y=138....(2)

so adding the two eqns. we have 7x=280 hence x=40

substituting x=40 in (1) we get 120+y=142⇒y=142-120=22.

hence the numbers are 40 and 22