Question

6. Find x if distance between P(2,-3) and Q(x,5) is 10 units​

Answer 1

109feet and chop of salt in hindi as a form

Answer 2

Given:

Here ,

• x 1 = 2 and y1 = -3

• x2 = x and y2 = 5

• D = 10 units

To find :

• The value of x

Solution :

As we know that :

$\star \boxed{ \bold{ {d}^{2} = ({x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} }}$

put the given values :

$\implies \: \: {10}^{2} = {(x - 2)}^{2} + ( {5 - ( - 3))}^{2} \\ \\ \implies \: 100 = {x}^{2} + 4 - 4x + 64 \\ \\ \implies \: {x}^{2} - 4x - 32 = 0 \\ \\ \implies \: {x}^{2} - 8x + 4x - 32 = 0 \\ \\ \implies \: x(x - 8) + 4(x - 8) = 0 \\ \\ \implies \: (x + 4)(x - 8) = 0 \\ \\ \implies \: x \: = - 4 \: and \: 8$

HENCE, THE VALUE OF X IS 8 UNITS