6. Finely divided catalyst has greater surface area and has greater catalytic activity than the compact
then howmany splits should be made to a cube of exactly 1cm in length to achieve required surface
solid. If a total surface area of 6291456cm2 is required for adsorption in a catalysed gaseous reaction,
areas. (Given: One split of a cube gives eight cubes of same size)
B) 80
C) 20
D) 22
A) 60
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Answer:
Area = 6×(Lenght)×(Length)
Length after n splits = 1/2n
Total surface area after n splits = 8n×6×(Length)×(Length)
8n×6×(1/2n)×1/2n)
(8n/4)×6
2n×6
2n×6 = 6291456
2n = 1048575
n×0.3010 = 6.0206
n = 6.0206/0.3010
n = 20 splits
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