Question

6. For what value K, is -3 a Zero of the polynomial x^2+11+k?
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Answer 1

Step-by-step explanation:

f(x) = x^2 +11 +k

f(-3) = 0

on puting x=-3 in f(x)

f(-3) = (-3)^2 +11 +k

0 = 9+11 +k

0 = 20 +k

k = -20

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