Math, asked by nischayruined9pcxyxt, 11 months ago

6. From the following figure find,
(1) x
(ii) angle ABC
(iii) angle ACD

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Answers

Answered by shreya1928
8
4x + 3x + 4x + 48 + x = 360
12x + 48 =360
12x = 360-48
x. = 312➗12
x =. 26



Hope you get the answer
Answered by kunwardurgesh3635
6

Answer:

Step-by-step explanation:

IF ACB = x

In triangle ABC,

angle ABC + angle ACB + angle BAC = 180 degree

4x + 3x + x = 180

8x = 180

x = 22.5

IF DCB = 3x

In quadrilateral ABCD,

angle ADC + angle DAB + angle ABC + angle BCD = 360 degree

4x + 48 + x + 4x +3x = 360

12x + 48 = 360

12x = 360 - 48

12x = 312

x = 26

Now you can multiply the value of x with the respective angles

i am sorry i didn't understand if the value of angle BCD is 3x or ACB is 3x.

HOPE YOU UNDERSTOOD!

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