Math, asked by mak178786, 6 months ago

6. From the sum of m2 - 2n2 and 4m2 - 9n2 + 15, subtract
the sum of 6m2 - 5n2 + 5 and m2 - 4n2 + 20.​

Answers

Answered by GaganpreetGill
2

Answer:

( m^2 - 2n^2 ) + ( 4m^2 - 9n^2 + 15 )

m^2 + 4m^2 -2n^2 -9n^2 +15

5m^2 - 11n^2 +15

( 6m^2 -5n^2 +5) + ( m^2 - 4n^2 + 20)

6m^2 +m^2 -5n^2 -4n^2 +5 +20

7m^2 -9n^2 +25

( 5m^2 - 11n^2 +15) - ( 7m^2 - 9n^2 +25)

5m^2 -11 n^2 +15 - 7m^2 +9n^2 -25

5m^2 -7m^2 -11n^2 +9n^2 +15 - 25

-2m^2 -2n^2 - 10

Hope this answer helps you friend ♥️

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