6 g of c was completely burnt in o2 whaf would be the volume of co2 produced at stp and how many molecules will be present
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C+O2-CO2
1 mole of C-12g
6 g-0.5 mole
1 mole of CO2=22.4L
0.5 mole of CO2=11.2L
1 mole =6.022*10^23 molecules
0.5 mole =3.011*10^23 molecules
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1 mole of C-12g
6 g-0.5 mole
1 mole of CO2=22.4L
0.5 mole of CO2=11.2L
1 mole =6.022*10^23 molecules
0.5 mole =3.011*10^23 molecules
Hope it helps
If yes please mark brainliest
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