6 g of magnesium reacts with oxygen to produce 10 g of magnesium oxide. How many
grams of oxygen is required to convert 50 g of magnesium into magnesium oxide?
Answers
Explanation:
The idea here is that chemical reactions must obey the Law of Mass Conservation, which states that when a chemical reaction takes place, the total mass of the reactants must be equal to the total mass of the products.
In your case, magnesium metal and oxygen gas are the reactants and magnesium oxide is the product.
2
Mg
(
s
)
+
O
2
(
g
)
→
2
MgO
(
s
)
You know that
10.0 g
of magnesium take part in this reaction and that
16.6 g
of magnesium oxide are produced.
You can say that the difference between the mass of the product and the total mass of the reactants, i.e. the mass of magnesium and the mass of oxygen gas, will give you the mass of oxygen gas that took part in the reaction.
m
Mg
+
m
O
2
=
m
MgO
−−−−−−−−−−−−−−−−−−
→
the Law of Mass Conservation
You will thus have
m
O
2
=
m
MgO
−
m
Mg
m
O
2
=
16.6 g
−
10.0 g
=
6.6 g
−−−−
The answer is rounded to one decimal place.