Question

6. Give zeroes of the polynomial p(x) = (x - 1)(x - 2) (x-3)(x-4)​

Answer 1

Answer:

zeroes are :x=1,2,3,4

Answer 2

ANSWER

Zeroes of the polynomial p(x)=(x-1)(x-2)(x-3)(x-4)

are 1, 2, 3 and 4

At x=1

p(1)=(1-1)(1-2)(1-3)(1-4)=0

Hence 1 is a zero of p(x).

At x=2

p(2)=(2-1)(2-2)(2-3)(2-4)=0

Hence 2 is a zero of p(x).

At x=3

p(3)=(3-1)(3-2)(3-3)(3-4)=0

Hence 3 is a zero of p(x).

At x=4

p(4)=(4-1)(4-2)(4-3)(4-4)=0

Hence 4 is a zero of p(x)