Question

6. Given A(4,-3) & B (8,5), Find the co- 2 points
ordinates of the point that divides
seg AB in the ratio 3:1.
O (-7,3)
0 (3.7)
O (7,3)
O (-7,3)
This is a required question​

Answer 1

Answer:

C) (7 , 3)

Step-by-step explanation:

Given,

A = (4 , -3)

B = (8 , 5)

Ratio = 3 : 1

To Find :-

Co-ordinate of the point that divides AB in the ratio 3:1

How To Do :-

Here they given the value of Co-ordinates of 'A' and 'B' and the ratio. We are asked to find the value of Co-ordinate of the point that divides AB in the ratio 3:1. So by using internal division formula we can obtain that

Formula Required :-

Internal division formula :-

$(x , y) = \left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Solution :-

Ratio = m : n

3 : 1 = m : n

A = (4 , -3)

Let,

x_1 = 4 , y_1 = -3

B = (8 , 5)

Let,

x_2 = 8 , y_2 = 5

Substituting in the formula :-

= [(3(8)+1(4))/3+1 , (3(5)+1(-3))/3+1 ]

= [ (24 + 4)/4 , (15 - 3)/4 ]

= [ 28/4 , 12/4 ]

= [ 7 , 3 ]

= (7 , 3)

Co-ordinate of the point = (7 , 3).

Option 'C' = (7 , 3)