Question

6 gm nitrogen on successive reactions with different compound gets finally converted into 30 gm Cr(NH3)xBr2 . value of x is

Answer 1

Molecular mass of the final compound is

52 + 17x + 160 = 212+17x which contains 14x g of Nitrogen

30 g of the final compound will contain 30 * 14x / (212+17x) of nitrogen = 6 g

420 x = 1272 + 102x

x = 1272/318 = 4

x = 4

The final compound is Cr(NH3)4Br2