6 gm of glucose is mixed with water to prepare 100 gm soln of density 1.2 g /mol.
Calculate
1.strength of the soln
2.molarity
3.molality
4.mole fraction of solute
5.mole%of solute
Answers
Answered by
2
Explanation:
Molality =
mass of solvent in kg
no of moles of solute
Molar mass of glucose = 180g
Mass of glucose =10
No of moles of glucose =
180
10
=0.0556mol
the solution of glucose in water which is 10% w/W means 10 g of glucose in 100 g of solution
Mass of solvenyt=100-10=90 g =0.090 kg
Molality =
0.090
0.556
=0.617m
Hence, the correct option is B
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