6 gm of sucrose present in 100 ml of liquid whose density is 1.2 GM/ml then find W/w %
Answers
Given:-
→ Mass of sucrose = 6 gm
→ Volume of the liquid = 100 mL
→ Density of the liquid = 1.2g/mL
To find:-
→ Concentration of the solution [w/w %]
Solution:-
It is clear that sucrose is solute and the liquid is solvent.
Firstly, let's calculate the mass of solvent.
=> Mass = Volume × Density
=> Mass = 100 × 1.2
=> Mass = 120gm
We have got the mass of solute and solvent. So now, let's calculate the total mass of the solution:-
Mass of solution :-
= Mass of solute + Mass of solvent
= 6gm + 120gm
= 126gm
Hence, we have got mass of the solution as 126gm. Now let's calculate the concentration.
Concentration of a solution [w/w %]
= Mass of solute/Mass of solution × 100
= 6/126 × 100
= 600/126
= 4.76%
Thus, concentration of the solution [w/w %] is 4.76% .
Explanation:
Given:-
→ Mass of sucrose = 6 gm
→ Volume of the liquid = 100 mL
→ Density of the liquid = 1.2g/mL
To find:-
→ Concentration of the solution [w/w %]
Solution:-
- It is clear that sucrose is solute and the liquid is solvent.
Firstly, let's calculate the mass of solvent.
=> Mass = Volume × Density
=> Mass = 100 × 1.2
=> Mass = 120gm
- We have got the mass of solute and solvent. So now, let's calculate the total mass of the solution:-
Mass of solution :-
= Mass of solute + Mass of solvent
= 6gm + 120gm
= 126gm
- Hence, we have got mass of the solution as 126gm. Now let's calculate the concentration.
Concentration of a solution [w/w %]
= Mass of solute/Mass of solution × 100
= 6/126 × 100
= 600/126
= 4.76%
- Thus, concentration of the solution [w/w %] is 4.76% .