Question

6 gram of hydrogen gas react with 64 gram of Oxygen gas under specific condition in a vessel what is the amount of water produced in this reaction​

Answer 1

Answer:

first we see reaction by which form water

2H2+ O2--->2H2O

here we see 2mole hydrogen react with 1mole Oxygen form two mole water

we have

10gm hydrogen =5mole hydrogen

64gm Oxygen =2mol mole oxygen

we know according to above reaction

4gm hydrogen react with 32gm oxygen

so,

10gm hydrogen react with 80gm oxygen

but we have given amount of oxygen only 64 gm it means Oxygen is here limiting reagent .

now

all oxygen reat then 8gm hydrogen react and form 4mole of water .

hence option(c) is correct

Explanation:

Answer 2

Given:

Mass of Hydrogen = 6 gm

Mass of oxygen = 64 gm

To Find:

The amount of water produced in this reaction.

Calculation:

- The reaction by which water is formed is:

2 H2 + O2 → 2 H2O

- According to this equation, 4 gm of hydrogen reacts with 32 gm of Oxygen to form 36 gm of water.

⇒ 6 gm hydrogen will react with 48 gm of oxygen to produce 54 gm of water.

- Here, hydrogen is the limiting reagent.

- So, the amount of water produced in this reaction​  is 54 grams.