Question

6 gram of urea is dissolved in 54 gram of water find the relative lowering vapour pressure also molality of the solution

Answer 1

n1 =54/18=3

n2= 6/60=0.1

relative lowering of vapour pressure,

=n2/n1

=0.1/3=0.033

• molality=(6×1000)/(60×54)=1.85