Question

6 gram urea present in a kg of solvent find out it molility​

Answer 1

Answer:

100/36

Explanation:

wt. of solute =1Gm.

molecular wt. of solute =60

wt.of solvent in gram =6 gram

formula=wt of solute ×1000/molecular wt. of solute × wt of solute in gram

M= 1×1000/60×6

=100/36