Question

6 grams of a substance of molecular weight 106 was dissolved in 100ml . 10ml of this solution was pipetted out into a 1000ml flask and made up to the mark with distilled water. the molarity of the resulting solution is

Answer 1

Answer:

Explanation:

Given :

mass of solute = 6 g

molar mass = 106g

Volume = 100 ml

Solution:

M1V1 = M2V2

M1 = (mass/molar mass x volume) 1000

= (6/106x100)1000

= 0.56

M1V1 = M2V2

0.56 X 10 = M2 X 1000

M2 = 0.0056

Answer 2

Answer:

Given

Mask of solute - 10.6g

Molecular mass - 106

Volume -100ml

Now,

Molarity = 10.6/106* 1000/100

So M= 1 ( by solving)

Now using M1V1=M2V2 ------(1)

M1 = 1, V1= 10ml , V2 = 1000ml

We need to find the M2=??

Now molarity remain the same when we prepare solution of sugar and water molarityy remain in the glass and if we took a. Spoon and pore some solution of water and sugar ,,, so here 100ml and 10ml molarity remain same.

Now put values in (1)

1*10=M2 * 1000

M2= 0.01

Explanation: