Math, asked by gowtham6309, 8 months ago

6 grams of alloy M are mixed with 14 grams
of alloy N to make a new alloy. Metal X
makes up 4% of alloy M and 9% of alloy N.
Metal X accounts for what percent of the
weight of the new alloy. (Disregard the
percent sign.)

Answers

Answered by harekrishna5733
1

Answer:

Hope it helps you a lot

Step-by-step explanation:

Let x be the amount of first alloy mixed

let y be the amount of second alloy mixed

Copper in 1

st

alloy =

7

5

x

Copper in 2

nd

alloy =

7

3

x

Total copper =

7

5x+3y

Zinc in 1

st

alloy =

7

2

x

Zinc in 2

nd

alloy =

7

4

x

Total Zinc =

7

2x+4y

Both copper & zinc should be in ∣:∣ ratio

7

2x+4y

7

5x+3y

=1

5x+3y=2x+4y

3x=y ⟶(I)

we know both alloy should make 28kg

x+y=28 ⟶(II)

where y=3x

x+3x=28

x=7kg ⟶1

st

alloy

y=21kg ⟶2

nd

alloy

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