6 Harini distributed 50 chocolates,
among 4 kids, The share of the
first kid, twice the share of
second teid, thrice the share of
third kid and four times the
Share of fourth kid are all equal.
Find the number of chocolates
received by 3rd kid.
Answers
Answered by
0
Answer:
total chocolates=50
share of 1st kid be x
share of 2nd kid be 2x
share of 3rd kid be 3x
share of 4th kid be 4x
share of chocolates x+2x+3x+4x=50
10x=50
x=5
share of third child = 3x =3×5
=15
Answered by
0
Answer:
3rd kif has 8 chocolates
Explanation:
four kids A,B,C,D all together have 50 chocolates
So A+B+C+D =50
share if 1st KID =A,
twice share of second KID = 2B
thrice the share of 3rd KID = 3C
4 times share of 4th KID = 4D
All are equal => A=2B=3C=4D
if A has 12 choclates then B = 12/2=6, C= 12/3 = 4
D= 12/4 =3
A+B+C+D = 12+6+4+3= 25 it has to be 50. So Double all values
A= 24, B= 12, C=8 D=6 total is 50.
3rd KID C has 8 chocolates.
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