6. How many grams of oxygen is required for complete combustion of 29 g of butane as per the equation : c4h10 + 4.502 = 2co2 + 5h2o
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how many grams of oxygen is required for complete combustion of 29 g of butane as per the equation C4H10 + 4 5O2 - 2CO2 + 5H2O
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Explanation:
fatty acids by treating the fat with alkali. ... Higher saponification value for triglyceride indicates higher medium chain fatty acids.
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