6) i) If A = 30 then show that Sin³A= 3 SinA - 4 Sin³A
Answers
Answered by
0
Answer:
Please correct the LHS,
It should be Sin3A
Step-by-step explanation:
LHS = Sin3A = Sin3×30° = Sin90° = 1
RHS = 3SinA - 4 Sin³A = 3×Sin30 - 4×Sin³30
= 3/2 - 4×1/8 = 3/2 - 1/2 = 1
LHS = RHS
Hence, proved.
Answered by
0
Answer:
sin3A=sin3(30
o
)=sin90
o
=1
3sinA−4sin
3
A=3sin30
o
−4sin
3
30
o
=3(
2
1
)−4(
2
1
)
3
=
2
3
−
2
1
=1
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