Question

6. (i) (x2 + 3x + 2)2 - 8(x2 + 3x) - 4 = 0​

Answer 1

Answer:

2x^2+6x+4-8x^2-24x-4=0

-6x^2-18x=0

-6(x^2+3)=0

x^2+3=0/-6

x^2+3=0

x^2=-3

x=

$x = \sqrt{3}$