Question

6 identical capacitors joined in parallel and are charged with battery 10V.Now it is removed and joined in series with each other.what would be potential difference between plates in combination?

Answer 1

The potential difference between 6 identical capacitors initially joined in parallel and charged with battery 10V then removed and joined in series with each other is given as:

1. Let Q be the charge on each plate, C be the capacitance of each capacitor, V be the potential difference across each plate.

2. When connected in parallel, the net capacitance of all plates Cnet = C1 + C2 + C3 +C4 +C5 +C6 = 6C

3.The charge stored in each plate will be Q= CV = C×10 = 10C and Qnet = Cnet×V= 60C

4. Now potential difference between plates in combination joined in series with each other is V=Q/C = 10C/C = 10V

Answer 2

Explanation:

1. answer is 60V.because when we will add all the voltages of the individual serires capacitances we will have a common LCM and the value of the net charge60 will become the voltage.