Math, asked by puneethmaligi, 4 months ago

6.
If 2" = 256 then find the value of 20-3​

Answers

Answered by rajashreekolawale
0

Answer:

The value of x is 4.

Step-by-step explanation:

Given : Expression \frac{16^{-2}}{(256)^{1-x}}=4^{2x}(256)1−x16−2=42x

To find : The value of x ?

Solution :

Re-write the expression as,

\frac{(4^2)^{-2}}{(4^4)^{1-x}}=4^{2x}(44)1−x(42)−2=42x

\frac{(4)^{-4}}{(4)^{4(1-x)}}=4^{2x}(4)4(1−x)(4)−4=42x

(4)^{-4-4(1-x)}=4^{2x}(4)−4−4(1−x)=42x

Comparing the base,

-4-4+4x=2x−4−4+4x=2x

-8=-2x−8=−2x

x=\frac{8}{2}x=28

x=4x=4

Therefore, the value of x is 4.

#Learn more

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