6.
If 2" = 256 then find the value of 20-3
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Answer:
The value of x is 4.
Step-by-step explanation:
Given : Expression \frac{16^{-2}}{(256)^{1-x}}=4^{2x}(256)1−x16−2=42x
To find : The value of x ?
Solution :
Re-write the expression as,
\frac{(4^2)^{-2}}{(4^4)^{1-x}}=4^{2x}(44)1−x(42)−2=42x
\frac{(4)^{-4}}{(4)^{4(1-x)}}=4^{2x}(4)4(1−x)(4)−4=42x
(4)^{-4-4(1-x)}=4^{2x}(4)−4−4(1−x)=42x
Comparing the base,
-4-4+4x=2x−4−4+4x=2x
-8=-2x−8=−2x
x=\frac{8}{2}x=28
x=4x=4
Therefore, the value of x is 4.
#Learn more
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