Question

6. If 2 and -3 are the zeroes of the quadratic
polynomial x² + (a + 1)x + b, then find the
value of a and b.​

Answer 1

Answer:

a = 0

b = -6

Step-by-step explanation:

Substituting X=2

4 + (a+1)2 + b = 0

2a+b+ 6 = 0  -----Eq (1)

Substituting X= -3

9 + (a+1) (-3) + b =0

-3a + b+ 6 = 0 -------Eq (2)

From eq 1 and 2,

a = 0

b = -6