Question

6.
If ū= 21-25 +3k and the final velocity is
J = 21 – 4j+5k and it is covered in a time of
10 sec, find the acceleration vector.​

Answer 1

Answer:

acceleration equal to 17 + 8k - 4j

Answer 2

Answer:

Explanation:

initial velocity = u= 21i + 15j + 3k

final velocity = v = 21i + 4j + 5k

t =10s a=?

now from first equation of motion we know-

v= u + at

21i + 4j + 5k= 21i + 15j + 3k + a*10

(21-21)i + (4-15)j + (5-3)k =10a

-11j + 2k=10a

a= (-11j + 2k)/10