Question

6 If 2cosӨ =√3 , then find all the trigonometric ratios of angle Ө​

Answer 1

Answer:

2cos∅=√3

cos∅ = √3/2 = b/h

p^2 = h^2 - b^2

p^2 = 2^2 - √3^2 = 4-3 = 1

p = √1 = 1

here, p= perpendicular, b=base, h=hypotenuse

sin∅= p/h = 1/2

tan∅ = p/b = 1/√3

cot ∅ = b/p = √3/1 = √3

sec∅ = h/b = 2/√3

cosec ∅ = h/p = 2/1 = 2.