Question

6. If 2x^2 + (2p - 13)x + 2 = 0 has a root 3, then the value of p is what?
​

Answer 1

Solution :

Given Equation,

2x² + (2p - 13)x + 2 = 0

3 is a root of the above quadratic equation

To finD : p

3 is a root of the given equation,on putting it back in the equation we would get the value of p

Putting x = 3 in the equation,

2(3)² + (2p - 13)(3) + 2 = 0

→ 20 + 6p - 39 = 0

→ 6p = 19

→ p = 19/6

Thus for x = 3,p would be 19/6

Answer 2

≡QUESTION≡

Find the value of p if 3 is the root of the equation , 2x² + (2p-13)x  + 2 = 0

                                                         

║⊕ANSWER⊕║

The Given Equation

$2x^{2} + (2p-13)x + 2 = 0$

Substituting x = 3 in the above equation

$2(3)^{2} + (2p-13)3 + 2 = 0$

$18 + 6p - 39 + 2 = 0$

$6p - 19 = 0$

$6 p = 19$

p = 19/6