Math, asked by sonusid, 7 hours ago

6.

If 6 water tanks can be filled by pipe in 47/2 hours, how long does the pipe take to fill 4 such water
tanks?​

Answers

Answered by Anonymous
42

Answer:

Given:

If 6 water tanks can be filled by pipe in  \frac{47}{2} hours, how long does the pipe take to fill 4 such water tanks?

To Find:-

The time taken for pipe to fill 4 water tanks.

Note:-

First, we will find the time taken by pipe to fill 1 water tanks by 6 water tanks time ÷ 6 and then for 4 water tanks, 1 water tanks time will be 4 times more ( unitary method ).

Fractions can't be divided easily so we use here reciprocal method. For example -  \frac{n}{d} ÷ 6 \ \ reciprocated \ \ to \ \ \frac{n}{d} × \frac{1}{6}

Solution:-

 \huge\pink{6 \ \ water \ \ tanks} =  \frac{47}{2} \ \ hours ,  \huge\pink{4 \ \ water \ \ tanks}  = ?

According to note first point ( unitary method )~

▪︎ 6 \ \ water \ \ tanks = \frac{47}{2} \ \ hours

▪︎ 1 \ \ water \ \ tank = \frac{47}{2} ÷ 6 \ \ hours

According to note second point ( reciprocal )~

▪︎ 1 \ \ water \ \ tank = \frac{47}{2} × \frac{1}{6} \ \ hours

▪︎ 1 \ \ water \ \ tank = \frac{47}{12} \ \ hours

 \huge\red{1 \ \ water \ \ tank \ \ time \ \ taken \ \ to \ \ be \ \ filled} =  \frac{47}{12} \ \ hours

__________________________

[ Now, we will calculate for 4 water tanks ]

According to note first point only~

▪︎ 4 \ \ water \ \ tanks = 1 \ \ water \ \ tank \ \ time \ \ taken × 4

▪︎ 4 \ \ water \ \ tanks = \frac{47}{12} \ \ hours × 4

▪︎ 4 \ \ water \ \ tanks = \frac{188}{12} \ \ hours

After reducing in its lowest term~

▪︎ 4 \ \ water \ \ tanks = \frac{47}{3} \ \ hours

Mixed fraction~

▪︎ 4 \ \ water \ \ tanks = 15 \ \frac{2}{3} \ \ hours

Answer:-

Hence, the pipe will take  15 \ \frac{2}{3} \ \ hours \ \ "or" \ \ \frac{47}{3} \ \ hours .

:)

Answered by vikramsehrawat145
1

Answer:

Answer:

Given:

If 6 water tanks can be filled by pipe in \frac{47}{2}

2

47

hours, how long does the pipe take to fill 4 such water tanks?

To Find:-

The time taken for pipe to fill 4 water tanks.

Note:-

●》First, we will find the time taken by pipe to fill 1 water tanks by 6 water tanks time ÷ 6 and then for 4 water tanks, 1 water tanks time will be 4 times more ( unitary method ).

●》Fractions can't be divided easily so we use here reciprocal method. For example - \frac{n}{d} ÷ 6 \ \ reciprocated \ \ to \ \ \frac{n}{d} × \frac{1}{6}

d

n

÷6 reciprocated to

d

n

×

6

1

Solution:-

\huge\pink{6 \ \ water \ \ tanks} 6 water tanks = \frac{47}{2} \ \ hours

2

47

hours , \huge\pink{4 \ \ water \ \ tanks} 4 water tanks = ? =?

☆ According to note first point ( unitary method )~

▪︎ 6 \ \ water \ \ tanks = \frac{47}{2} \ \ hours 6 water tanks=

2

47

hours

▪︎ 1 \ \ water \ \ tank = \frac{47}{2} ÷ 6 \ \ hours 1 water tank=

2

47

÷6 hours

☆ According to note second point ( reciprocal )~

▪︎ 1 \ \ water \ \ tank = \frac{47}{2} × \frac{1}{6} \ \ hours 1 water tank=

2

47

×

6

1

hours

▪︎ 1 \ \ water \ \ tank = \frac{47}{12} \ \ hours 1 water tank=

12

47

hours

\huge\red{1 \ \ water \ \ tank \ \ time \ \ taken \ \ to \ \ be \ \ filled}1 water tank time taken to be filled = \frac{47}{12} \ \ hours

12

47

hours

__________________________

[ Now, we will calculate for 4 water tanks ]

☆ According to note first point only~

▪︎ 4 \ \ water \ \ tanks = 1 \ \ water \ \ tank \ \ time \ \ taken × 4 4 water tanks=1 water tank time taken×4

▪︎ 4 \ \ water \ \ tanks = \frac{47}{12} \ \ hours × 4 4 water tanks=

12

47

hours×4

▪︎ 4 \ \ water \ \ tanks = \frac{188}{12} \ \ hours 4 water tanks=

12

188

hours

☆ After reducing in its lowest term~

▪︎ 4 \ \ water \ \ tanks = \frac{47}{3} \ \ hours 4 water tanks=

3

47

hours

☆ Mixed fraction~

▪︎ 4 \ \ water \ \ tanks = 15 \ \frac{2}{3} \ \ hours 4 water tanks=15

3

2

hours

Answer:-

Hence, the pipe will take 15 \ \frac{2}{3} \ \ hours \ \ "or" \ \ \frac{47}{3} \ \ hours 15

3

2

hours "or"

3

47

hours .

:) This is right answer

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