6) If A={1,2,3} B={1,2,3,4,5,6} find n(B)
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Answered by
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basically (A*B) is relation from set A having elements 1,2,3,4,5,6 to set B having elements 1,3,5,7 .
So we will different different ordered pair like
For ex. From set A if we pick 1 we have four choices to map it with 1,3,5,7 which are in 8 so like this way each element in set A has 4 choices so total no. Of ordered pair will be 6*4= 2
Answered by
0
Answer. n(A union B)= n(A)+ n(B) - n(A intersection B)-n(A)
Step-by-step explanation:
hope this will be useful
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