Question

6. If a = 3, b = – 2, с = – 1, verify that :
(i) bx (a + с) = bxa+bxc (ii) bxсxa = axbx c = cxахь
(iii) bx c = c x​

Answer 1

Answer:

(I) (-2) × (3-1) = (-2×3) + {-2×(-1) }

(-2) ×2 = -6+2

-4 = -4

(ii) (-2) ×(-1) ×3 = 3×(-2) ×(-1) = (-1) ×3×(-2)

6 = 6 = 6

(iii) bx c = c x...?