Question

6)if A=5500;P=5000;R=10% find T *
O 2 years
O none
O 10 years
O 1 year​

Answer 1

Answer:

⭐⭐ Here is your answer ⭐⭐

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< u > < b > Compound Interest :- < /b > < /u ><u><b>CompoundInterest:−</b></u>

Compounding at Annually:

Principle = ₹5000

Rate of interest = 10%

Number of years = 2years

Amount = P (1 + \frac{R}{100}

100

R

)^n

= 5000 (1 + \frac{10}{100}

100

10

)^2

= 5000 (\frac{11}{10}

10

11

)

= 5000 (\frac{11}{10}

10

11

)( \frac{10}{100}

100

10

)

= ₹6050

C.I = Amount - Principle

= 6050 - 5000

= 1050

< u > < b > Simple Interest :- < /u > < /b ><u><b>SimpleInterest:−</u></b>

Principle = ₹5000

Rate of interest = 10%

Number of years(time)= 2years

Simple Interest = {P×R×T}{100}P×R×T100

= {5000×10×2}{100}5000×10×2100

= ₹1,00,000

1 year ans

Answer 2

Answer:

Simple Interest - 5500-5000= ₹500

$simple \: interest = \frac{time \times rate \times principal}{100}$

$500 = \frac{5000 \times time \times 10}{100} \\ \\ time = \frac{500 \times 100}{5000 \times 10} \\ \\ = \frac{5}{5} \\ \\ 1years \:$

So, time = 1year