Question

6. If a, ß are the zeros of polynomial f(x) = x? - p(x + 1) - C, then (a + 1) (B + 1) =
qx + px +1
(a) C-1 (b) 1-C
(c) c
(d) 1+c
​

Answer 1

Answer:

(b) 1-c

Step-by-step explanation:

We know given that the zeroes α and β of a quadratic function y=f(x),

α+β=-coefficient of x/coefficient of x²

αβ=constant/coefficient of x²

Here,

coefficient of x²=1

coefficient of x=-p

constant=-p-c

$(\alpha+1)(\beta+1)\\=\alpha\beta+\alpha+\beta+1\\=\frac{-p-c}{1} +\frac{-(-p)}{1}+1\\\\=-p-c+p+1=1-c$

So, the answer is 1-c.

Hope it helps!

<3