6. If a2 + b2 = 34 and ab = 12 : find;
1. 3 ( a+b )2 + 5(a-b)2
2. 7 (a-b)2 - 2(a+b)2
ans..1 ...224
ans...2... -46
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Answered by
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a²+b²=34, ab=12
1.
3(a+b)²+ 5(a-b)²
= 3a²+3b²+6ab+5a²+5b²-10ab
= 3(a²+b²)+5(a²+b²)-4ab
= 8(a²+b²)-4ab
= 8×34-4×12
= 272-48
= 224
2 sum is same as 1
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