Question

6. If an object of height 4 cm is placed at distance of 12 cm from a concave mirror having focal
length 24 h find the position, nature and the height of the image.

7) A ray of light enters from water to glass. Refractive index of glass with respect to water is 1.12.
Find absolute refractive index of water if absolute refractive index of glass is 1.5.​
plz solve both of these

Answer 1

Answer:

position= at 24 cm ,

nature = real image

height of image= 8

Explanation:

given information is ,

height of object = 4 cm

by applying sign convention we get the following,

object distance (u) = -- 12 cm

focal length (f) = --24 cm

let image distance =(v)

we have mirror formula,

1/f= 1/u+1/v

1/-24= 1/-12 + 1/v

we get v=+24 cm

here '+' sign indicates it's a real image

now magnification (m) = --(v)/(u)

m= -- 24/ --12

m= +2 ---------(1)

we also have another formula for magnification i.e.,m= height of image / height of object

m= h(i)/h(o)-----------(2)

from equation (1),(2)we get,

2=h(i)/4

h(i) = 8 cm

height of image = 8 cm