Question

6. If difference between the squares of two consecutive numbers is 47. Find the smaller number.
(a)21 (b)22 (c)23 (d)24

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Answer 1

let the consecutive number be

x,(x+1) {where (x+1)>x}

a/q

(x+1)^2-x^2=47

x^2+2x+1-x^2=47

2x=47-1

2x=46

x=23

so the correct option is (c)23

Answer 2

Hope this helps you.......


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