Question

6.
If I and E are ionisation energy and electron affinity of an element in KJ mole-1, electrons
tivity is given as:
I.E+E.A
A)
B)
I. E+E.A.
5.6
1. E+E.A.
129
C)
2
orie
1. E+E.A.
544
LEVEL - II
7
In a period electronegativity is given as​

Answer 1

Thus the value of electronegativity is E.N = I.P + E.A / 544

• The value of electronegativity on the Mulliken scale is
• E.N = I.P + E.A / 2
• The value of electronegativity on the Pauling scale is
• E.N = I.P + E.A / 2 + 2.8
• Both ionization potential and electron affinity are measured in kilojoule per mole i.e Kj/mol.
• Now
• E.N = I.P + E.A / 2 x 2.8 x 96
• E.N = I.P + E.A / 544

So, the correct answer is D

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