Question

6. If log10(x² - 5x+7)=0 then x=​

Answer 1

x=3(or)x=2

Step-by-step explanation:

log base 10(x^2-5x+7)=0

x^2-5x+7=10^0

x^2-5x+7=1

x^2-5x+7-1=0

x^2-5x+6=0

x^2-3x-2x-2x+6=0

x(x-3)-2(x-3)=0

(x-3)(x-2)

here the answer x=3 (or)x=2