Question

6. If p = 4, q = -3 and r = 2, find the value of : p3 +93 – p3 – 3pqr.
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Answer 1

$\large \mathsf {\underline {\underline{Quetion}}} : -$

. If p = 4, q = -3 and r = 2, find the value of : p3 +93 – p3 – 3pqr.

$\large \mathsf{ \underline{ \underline{Solve}}} : -$

4× ( 3) + 93 - 4 × ( 3 ) - 3 × ( 4)(-3(2)

= 12-267 + 72

= -183

so, answer is - 183

Example:-

if x= 2 , p = 3

solve: 3p + 2x - 2p

=3(3) + 2 ( 2) - 2(3)

=9+ 4- 6

= 7

so in example 7 is the answer