Question

6. If p, q are the zeroes of (x2 - 7x + k) and if p - q = 3, find K.

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Answer 1

let two zeros be alpha and bita

a/q

alpha-bita=3_________1

then alpha+bita=-b/a=-(-7)/1=7________2

solving 1 and 2 we get

alpha=5 and bita=2

put x=5 in x2-7x+k

and put x=2 in x2-7x+k

we get k=-11 or k=10