Question

6. If p(x) = x^3 + 3x^2 - 2x +4, then find the value of
p(2) + p(-2) - p(0).
[CBSE 2012​

Answer 1

Answer:

28

Step-by-step explanation:

p(x) = x^3 + 3x^2 - 2x + 4

p(2) = 2^3 + 3(2)^2 - 2(2) + 4

      = 8 + 12 - 4 + 4

      = 20

p(-2) = (-2)^3 + 3(-2)^2 - 2(-2) + 4

        = - 8 + 12 + 4 + 4

        = 12

p(0) = (0)^3 + 3(0)^2 - 2(0) + 4

       = 0 + 0 - 0 + 4

       = 4

Hence,

p(2) + p(-2) - p(0) = 20 + 12 - 4

                            = 28

Answer 2

Answer

p(2) + p(-2) - p(0) = 28

Step By Step Explanation

p(2) + p(-2) - p(0)

= [2³ + 3(2)² - 2(2) + 4] + [(-2)³ + 3(-2)² - 2(-2) + 4] - [0³ + 3(0)² - 2(0) + 4]

= [8 + 3(4) - 4 + 4] + [-8 + 3(4) - (-4) + 4] - [0 + 3(0) - 0 + 4]

= [8 + 12 - 4 + 4] + [-8 + 12 + 4 + 4] - [0 + 0 - 0 + 4]

= [8 + 12] + [-8 + 12 + 8] - [4]

= 20 + 12 - 4

= 32 - 4

= 28