Question

6. If POR is a line, find a.



Pls help me​

Answer 1

$\huge\mathfrak\purple {Answer:}$

If POR is a line,

Then ‹POR = 180°

→ ‹POQ + ‹POQ = 180°

According To Question,

(3a + 5)° + (2a - 25)° = 180°

→ 3a + 2a + 5 + (-25) = 180°

→ 5a + (-20) or 5a - 20 = 180°

→ 5a = (180 + 20)°

→ 5a = 200°

→ a = (200/5)°

→ a = 40°

Therefore,

a = 40°

$\huge\mathfrak\purple {Bonus:}$

The angles are:

→ (3a + 5) = (3 × 40) + 5 = 125°

→ (2a - 25) = (2 × 40) - 25 = 55°

$\mathfrak\purple {Hope\: this\: helps\: you...}$