Question

6. If secA + tanA = m and secA – tanA = n, find the value of mn .

Standard:- 10

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Answer 1

Hey mate,

Here is ur answer,

SecA+TanA =m

SecA-TanA = n

=> mn =(SecA+TanA)(SecA-TanA).

$= > \: mn = {sec}^{2} a - {tan}^{2} a$

We know that,

$= > \: {sec}^{2} a - {tan}^{2} a = 1$

$= > \: mn = 1$

:-)Hope it helps u. 《《 VIDYA 》》

Answer 2

Hey!!!!

Good Evening

As promised I am here to help you

Difficulty Level : Average

Chances of being asked in Board : 90%

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Given : secA + tanA = m and secA - tanA = n

To Find : mn

Solving Directly,

= mn

= (secA + tanA)(secA - tanA)

We know (a + b)(a - b) = a² - b²

= sec²A - tan²A

= 1 <<<<<<<<< Answer

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Hope this helps ✌️

Good Night :-)