6. If secA + tanA = m and secA - tanA = n, find the value of
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so u get answer as one
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secA +tanA=m,secA -tanA=n
now,
√mn= √(secA+tanA)(secA-tanA)
=√(sec²A-tan²A)
= √1
1
now,
√mn= √(secA+tanA)(secA-tanA)
=√(sec²A-tan²A)
= √1
1
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