Question

6. If the dimensions of a rectangle
are 15cm and 8cm, then the length
of its diagonal is *
​

Answer 1

Answer:

The diagonal is 17cm.

Step-by-step explanation:

Given dimensions of the rectangle :

• length = 15cm.
• breadth = 8cm.

Here, the length and the breadth of the rectangle is given we need to find the diagonal of the rectangle by using the formula of “Pythagoras”

We know that,

→ h² = p² + b²

Here,

• h (hypotenuse) = d (diagonal)
• p (perpendicular) = b (breadth)
• b (base) = l (length)

Or,

→ d² = l² + b²

• l (length) = 15cm.
• b (breadth) = 8cm.

From the given dimensions :

→ d² = 15² + 8²

→ d² = 225 + 64

→ d² = 289

→ d = √289

→ d = 17

∴ The diagonal of the rectangle is 17cm.

Note behind :

• We used the “Pythagoras theorem” where 'perpendicular' was taken as 'breadth' 'hypotenuse' is taken as 'diagonal' and also 'base' as length.

Answer 2

Answer :-

• Diagonal of Rectangle = 17 cm.

Explanation :-

Given :

• Length of Rectangle = 15 cm.
• Breadth of Rectangle = 8 cm.

To Find :

• Its Diagonal.

Solution :

We know that,

D = √(l² + b²)

Here,

• D = Diagonal.
• l = Length of Rectangle.
• b = Breadth of Rectangle.

So, Put the Values.

➠ D = √(15² + 8²)

➠ D = √(225 + 64).

➠ D = √289.

➠ D = 17 cm.

Therefore, Diagonal of Rectangle = 17 cm.