Question

6/ If the nth term of a progression is (4n-10) show that it is an AP. Find its


(i) first term, (ii) common difference, and (iii) 16th term.
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Answer 1

Arithmetic Progression

So nth term of an A.P. is 4n - 10

• aₙ ₊ ₁ - aₙ = d

→ aₙ ₊ ₁ - aₙ = 4(n + 1) - 10 - (4n - 10)

→ aₙ ₊ ₁ - aₙ = 4n + 4 - 10 - 4n + 10

→ aₙ ₊ ₁ - aₙ = 4 = d

Hence common difference is independent of variables therefore 4n - 10 exist in A.P.

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(i) First term :-

→ 4n - 10 = 4(1) - 10 = - 6

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(ii) Common difference = 4

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(iii) 16th term :-

→ 4(16) - 10 = 54

Answer 2

Hey there

refer to attachment