Question

6. If the polynomials x³ + ax² + 5 and x³-2x² +a are divided by (x + 2) leave the same remainder, find the value of a.​

Answer 1

Answer:

a= (-13)/3

Step-by-step explanation:

If both polynomials leave same remainder when divided by (x+2), then by substituting (-2) in both polynomials, the result must be same.

P(x1)= x³+ax²+5

P(-2)= (-2)³+a(-2)²+5

= -8+4a+5

= 4a-3. eq(1)

P(x2)= x³-2x²+a

P(-2)= (-2)³-2(-2)²+a

= -8-8+a

= a-16. eq(2)

Now eq(1)=eq(2)

4a-3=a-16

3a= -13

a= (-13)/3

Mark my answer as brainliest.

Cheers!