Question

6. If the radius of the circular base of a right circular cone is tripled, find the ratio of the volume of the first one to that of the second, the height remaining same.​

Answer 1

Answer:

Step-by-step explanation:

Let r be the radius of the circular base and h be the height of the cone.

Volume of first cone = 1/3 * πr²h  = πr²h/3

For the second cone,

radius = 3r, height = h.

Volume of second cone = 1/3 * π(3r)²h =  9πr²h/3

So ratio of Volume of first cone and second cone = πr²h/3 : 9πr²h/3

                                                                                    =  1 : 9

Answer 2

Let the radius and height of right circular cone 

Then volume V1=πr2h

If radius is half of radius =2r and height =h

Then volume V2=π(2r)2h=4πr2h

Then ratio V1:V2=πr2h:4πr2h=4:1