Question

6. If the work done by a body on application of a constant force is directly proportional to the distance travelled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also read from the graph the work done when the distance travelled by the body is

(i) 2 units

(ii) 0 unit




shreyansh are you here​

Answer 1

Answer:

x0 2 3  y05 10 

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)Putting the value x in (1)

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)Putting the value x in (1)y=5x

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)Putting the value x in (1)y=5xy=5×2=10.

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)Putting the value x in (1)y=5xy=5×2=10.Hence, Work done =10.

x0 2 3  y05 10 Let x units be the distance traveled by the body and y units be the work done by constant force.According to problem, y=5x     ...(1)Now , putting the value x=0 in (1)y=5×0=0So, the solution is (0,0)Putting the value x=1 in (1)y=5×1=5So, the solution is (1,5)Putting the value x=2 in (1)y=5×2=10So, the solution is (2,10)(i) When x=2 units (distance)Putting the value x in (1)y=5xy=5×2=10.Hence, Work done =10.(ii) When x=0 units

Answer 2

Heya Mate here's Your answer

Let x units be the distance traveled by the body and y units be the work done by constant force.

According to problem, y=5x ..(1)

Now , putting the value x=0 in (1)

y=5×0=0

So, the solution is (0,0)

Putting the value x=1 in (1)

y=5×1=5

So, the solution is (1,5)

Putting the value x=2 in (1)

y=5×2=10

So, the solution is (2,10)

(i) When x=2 units (distance)

Putting the value x in (1)

y=5x

y=5×2=10.

Hence, Work done =10.

(ii) When x=0 units (distance)

Putting the value x in (1)

y=5x

y=5×0=0.

Hence, work done =0.

Mark As Brainliest..